3x^2=223

Solution for 3x^2=223 equation:

3x^2=223

We move all terms to the left:

3x^2-(223)=0

a = 3; b = 0; c = -223;
Δ = b2-4ac
Δ = 02-4·3·(-223)
Δ = 2676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2676}=\sqrt{4*669}=\sqrt{4}*\sqrt{669}=2\sqrt{669}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{669}}{2*3}=\frac{0-2\sqrt{669}}{6}
=-\frac{2\sqrt{669}}{6}
=-\frac{\sqrt{669}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{669}}{2*3}=\frac{0+2\sqrt{669}}{6}
=\frac{2\sqrt{669}}{6}
=\frac{\sqrt{669}}{3}
$